var G_shuxue_data = {
    "ReturnMessage": "取数据成功",
    "StyleItems": [
        {
            "StyleID": 1,
            "Style": "单项选择题",
            "Explain": "单项选择题",
            "Score": 1,
            "Type": "ATEST",
            "TestCount": 5,
            "TestItems": [
                {
                    "ATestID": 16000004,
                    "AllTestID": 16000004,
                    "Title": "某品牌的电冰箱连续两次降价10%后的售价是降价前的（）",
                    "Explain": "设原始售价为单位“1”，则两次连续降价后的售价为1×（1-0.1)²=0.81，故，连续降价两次后的价格是降价前的81%",
                    "TestPoint": "增长率问题",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "80%"
                        },
                        {
                            "ItemName": "B",
                            "Content": "81%"
                        },
                        {
                            "ItemName": "C",
                            "Content": "82%"
                        },
                        {
                            "ItemName": "D",
                            "Content": "83%"
                        },
                        {
                            "ItemName": "E",
                            "Content": "85%"
                        }
                    ],
                    "Answer": "B",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                },{
                    "ATestID": 16000005,
                    "AllTestID": 16000005,
                    "Title": "甲、乙、丙三种货车的载重量成等差数列，2辆甲种车和1辆乙种车满载量为95吨，1辆甲种车和3辆丙种车满载量为150吨。则用甲、乙、丙各1辆车一次最多运送货物（）吨",
                    "Explain": "设甲、乙、丙的载重量分别为a,b,c吨，2b=a+c...............（1) a=30 ， 则  2a+b=95............（2），解得  b=35， a+3c=150..........（3）c=40，故a+b+c=105",
                    "TestPoint": "等差数列、简单方程应用",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "125"
                        },
                        {
                            "ItemName": "B",
                            "Content": "120"
                        },
                        {
                            "ItemName": "C",
                            "Content": "115"
                        },
                        {
                            "ItemName": "D",
                            "Content": "110"
                        },
                        {
                            "ItemName": "E",
                            "Content": "105"
                        }
                    ],
                    "Answer": "",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                },{
                    "ATestID": 16000006,
                    "AllTestID": 16000006,
                    "Title": "张老师到一所中学进行招生咨询，上午接受了45名同学的咨询，其中的9名同学下午又咨询了张老师，占张老师下午咨询学生的10%。一天中向张老师咨询的学生人数为（）",
                    "Explain": "根据“部分量/部分量的占比=总量”，得到下午的咨询学员有9/10%=90名。其中下午90名中有9名上午已经咨询过，所以下午新的咨询学员90-9=81名；故，一天中总的咨询学员45+81=126名。",
                    "TestPoint": "比例、集合应用",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "81"
                        },
                        {
                            "ItemName": "B",
                            "Content": "90"
                        },
                        {
                            "ItemName": "C",
                            "Content": "115"
                        },
                        {
                            "ItemName": "D",
                            "Content": "126"
                        },
                        {
                            "ItemName": "E",
                            "Content": "135"
                        }
                    ],
                    "Answer": "D",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                },{
                    "ATestID": 16000007,
                    "AllTestID": 16000007,
                    "Title": "某公司用1万元购买了价格分别是1750元和950元的甲、乙两种办公设备，则购买的甲、乙办公设备的件数分别为（）",
                    "Explain": "设购买甲、乙办公设备的件数分别为a,b，则1750a+950b=10000，化简有35a+19b=200，带选项验证，可得a=3,b=5",
                    "TestPoint": "实数、简单方程",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "3,5"
                        },
                        {
                            "ItemName": "B",
                            "Content": "5,3"
                        },
                        {
                            "ItemName": "C",
                            "Content": "4,4"
                        },
                        {
                            "ItemName": "D",
                            "Content": "2,6"
                        },
                        {
                            "ItemName": "E",
                            "Content": "6,2"
                        }
                    ],
                    "Answer": "A",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                },{
                    "ATestID": 16000008,
                    "AllTestID": 16000008,
                    "Title": "设随机变量X与Y独立，且X~N（1,2），Y~N（1,4），则D（XY）=(   )",
                    "Explain": "由提设知EX=EY=1,DX=2,DY=4，从而E（X²)=DX+(EX）²=3，E(Y²)=DY+(EY）²=5又由于X,Y相互独立，所以D（XY)=E(XY)²-(EXY)²=EX²EY²-(EXEY)²=14故选（C）",
                    "TestPoint": "略",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "6"
                        },
                        {
                            "ItemName": "B",
                            "Content": "8"
                        },
                        {
                            "ItemName": "C",
                            "Content": "14"
                        },
                        {
                            "ItemName": "D",
                            "Content": "15"
                        }
                    ],
                    "Answer": "C",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                },{
                    "ATestID": 16000010,
                    "AllTestID": 16000010,
                    "Title": "设函数f（X）具有2阶导数，g（x)=f(0）（1-x)+f(1）x，则在区间[0,1]上（  ）",
                    "Explain": "如果对曲线在区间[a,b]上凹凸的定义比较熟悉的话，可以直接做出判断． 显然g（x)=f(0）(1-x)+f(1)x就是联接（0,f(0))，(1,f(1))两点的直线方程．故f’’(X)≥0当时，曲线是凹的，也就是f(X)≤g（x），应该选（D）",
                    "TestPoint": "此题考查的曲线的凹凸性的定义及判断方法",
                    "SelectedItems": [
                        {
                            "ItemName": "A",
                            "Content": "当f’(X)≥0时，f(X)≥g（x）"
                        },
                        {
                            "ItemName": "B",
                            "Content": "当f’(X)≥0时，f(X)≤g（x）"
                        },
                        {
                            "ItemName": "C",
                            "Content": "当f’’(X)≥0时，f(X)≥g（x）"
                        },
                        {
                            "ItemName": "D",
                            "Content": "当f’’(X)≥0时，f(X)≤g（x）"
                        }
                    ],
                    "Answer": "D",
                    "IsFav": 0,
                    "UserNoteContent": "这题真好"
                }
            ]
        }
    ]
};